leet code
994 - Populating Next Right Pointers in Each Node
문제에서는 추가적인 공간을 사용하지 말라고 했는데,
그것까지는 고려하지 못 해서 아쉽습니다.
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48 | /*
// Definition for a Node.
class Node {
public:
int val;
Node* left;
Node* right;
Node* next;
Node() : val(0), left(NULL), right(NULL), next(NULL) {}
Node(int _val) : val(_val), left(NULL), right(NULL), next(NULL) {}
Node(int _val, Node* _left, Node* _right, Node* _next)
: val(_val), left(_left), right(_right), next(_next) {}
};
*/
#include<queue>
class Solution {
public:
Node* connect(Node* root) {
if(!root) return nullptr;
queue<Node*> q;
q.push(root);
while(!q.empty())
{
int len_q = q.size();
for(int i=0; i<len_q; ++i)
{
Node* cur = q.front();
q.pop();
if(i+1<len_q){
cur->next = q.front();
}else{
cur->next = nullptr;
}
if(cur->left)
q.push(cur->left);
if(cur->right)
q.push(cur->right);
}
}
return root;
}
};
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